this post was submitted on 13 May 2025
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Science Memes

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[–] blackbrook@mander.xyz 81 points 3 weeks ago (3 children)

That doesn't work anyway, since based on wheat variety, growing season, and grinding method, different flours have different information density.

[–] ArmoredThirteen@lemmy.zip 36 points 3 weeks ago (1 children)

They have an international prototype sack of flour in an old missile silo in Kansas. Ultimately that's what all the measurements are relative to

[–] Natanael@infosec.pub 2 points 3 weeks ago

Computational biochemists are working with a crack team of mathematicians as we speak to develop an alternative standard which does not need a reference mass

[–] SkaveRat@discuss.tchncs.de 25 points 3 weeks ago (1 children)

I like to read bedtime stories to my wheat, so it learns more and has higher information density

[–] Natanael@infosec.pub 3 points 3 weeks ago

I just plug mine into USB ports

[–] Clent@lemmy.dbzer0.com 4 points 3 weeks ago (1 children)

Sounds like the culinary world would benefit from having a measurement system that accounts for these factors.

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[–] Zip2@feddit.uk 56 points 3 weeks ago (26 children)

Still a more acceptable measurement than “1 cup”.

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[–] Redjard@lemmy.dbzer0.com 54 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

Wouldn't this make the units temperature-dependent?

Landauer limit is one kTln2 per bit of information, so at 300K about 3 zeptojoule per bit.
Dividing by c² we get 32 micro-quectogram per bit, so 32 yoctogram per terabit. 256 yoctogram per terabyte.
The Author wants half a septillion terabytes, 0.5•10²⁴ terabytes, half a yotta-terabyte.
That makes 128 grams.

Since I don't know what on earth "a cup of flour" is, I can't judge if the comic character proposes a reasonable conversion, but 0.1kg seems like a reasonable amount to use in cooking.

For baking I would rather have my units temperature dependent than density dependent (I can compact my flour or work with water or nuts, all having different densities, but my room temperature will always be roughly 300).
I endorse einstein-landauer units.

[–] zalgotext@sh.itjust.works 15 points 3 weeks ago (9 children)

184 grams is a touch high for "a cup of flour", but I'm not gonna check your math, and the comic probably wanted to use "close enough" round-ish numbers. The weight of a cup of flour is usually somewhere between 120g and 145g, going by the conversions used by major baking recipe publishers like King Arthur, Cooks Illustrated, Washington Post, New York Times, etc.

[–] Redjard@lemmy.dbzer0.com 12 points 3 weeks ago

I fear their apartment is at -50°C and this is a cry for help.

At least I am relieved to know that even acclaimed authors native to the cup-measurement system don't know what "a cup of flour is".

I'll be off baking my pannenkoek with 150g of flour then.

[–] Redjard@lemmy.dbzer0.com 8 points 3 weeks ago

I figured it out. Typed the ln2 into my text and then forgot it in the calculator.
Great, I'ma redo alll my numbers then rq

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[–] HawlSera@lemm.ee 29 points 3 weeks ago (5 children)

Information is physical? I'm gonna need a source on that one.

[–] cholesterol@lemmy.world 20 points 3 weeks ago (1 children)

The idea is that information must have a physical representation. But I don't know how that would lead to a standardized mass of a byte.

[–] vithigar@lemmy.ca 21 points 3 weeks ago* (last edited 3 weeks ago) (2 children)

No, you missed the point. See @milicent_bystandr@lemm.ee's comment and link to Landauer's Principle, the namesake of which is literally named in the title of the post.

TL;DR: Storing information requires a change in entropy. A change in entropy requires a change in energy. There must be a minimum non-zero amount of energy required for a given quantity of information. Energy is mass due to mass-energy equivalence. ∴ information has mass independent of its physical representation.

[–] cholesterol@lemmy.world 2 points 3 weeks ago (2 children)

There must be a minimum non-zero amount of energy required for a given quantity of information.

Okay, but I still don't get how that leads to a standardized measure of energy/mass for a given amount of bytes. That seems to be the premise of the comic.

information has mass independent of its physical representation.

So what is the mass of a byte of 'pure' information? And how do you derive it?

[–] vithigar@lemmy.ca 16 points 3 weeks ago (1 children)

So what is the mass of a byte of ‘pure’ information? And how do you derive it?

That's all in the linked wikipedia article, but since you asked:

At room temperature, the Landauer limit represents an energy of approximately 0.018 eV (2.9×10^−21^ J).

That's 1 bit, so 1 byte is eight times that, which you can plug into E=mc^2^ to get its absurdly small equivalent mass.

It's important(?) to note that Landauer's Principle is not settled science and has yet to be rigorously proven, unless there's some recent development which the comic is referencing. I haven't checked.

[–] cholesterol@lemmy.world 2 points 3 weeks ago (1 children)

That’s all in the linked wikipedia article

I appreciate you spelling some of it out, because I'm just curious and don't have the background knowledge to really navigate this.

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[–] lennivelkant@discuss.tchncs.de 2 points 3 weeks ago

When referencing another person's comment, it can be helpful to link to that comment or the article you mentioned.

I'd also like to point out that many Wikipedia articles, particularly those written by experts on a given scientific subject, tend to be daunting rather than helpful for people not yet familiar with that subject.

Explanations like the one you offered in this comment and the next reply can help make topics more approachable, so I very much appreciate that.

To illustrate my point:

In this case, the article first describes the principle as "pertaining to a lower theoretical limit of energy consumption of computation", which doesn't directly highlight the connection to information storage. The next sentence then mentions "irreversible change in information" and "merging two computational paths", both of which are non-trivial.

From a brief glance at the article on reversible computing linked further on, I gather that "irreversible" here doesn't mean "you can't flip the bit again" but rather something like "you can't deterministically figure out the previous calculation from its result", so the phrase boils down to "storing a piece of information" for our context. The example of "merging computational paths" probably has no particular bearing on the energy value of information either and can be ignored as well.

Figuring out the resulting logic that you so kindly laid out – again, thank you for that! – requires a degree of subject-specific understanding to know what parts of the explanation can be safely ignored.

Of course, experts want to be accurate and tend to think in terms they're familiar with, so I don't fault them for that. The unfortunate result is that their writings are often rather intransparent to laypeople and linking to Wikipedia articles isn't always the best way to convey an understanding.

[–] Natanael@infosec.pub 12 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

Entropy in information theory is equivalent to entropy in quantum dynamics / thermodynamics

[–] kameecoding@lemmy.world 9 points 3 weeks ago

i will Physically bitchslap you then you can deduce yourself the information about whether your face hurts or not, ayy lmao.

At least that's how I choose to interpret this new information

[–] LanguageIsCool@lemmy.world 3 points 3 weeks ago

I’d give a source but it’s physically in my house and it’s heavy

[–] Midnitte@beehaw.org 22 points 3 weeks ago

Oh sure, throw a fit — just wait until you want to convert those units to kilojoules!

Who's laughing now, tablespoons?!

[–] WanderingThoughts@europe.pub 17 points 3 weeks ago

Hundred sextillion terabytes. Yeah, everybody of calling it hungry sex bites in minutes.

[–] Sedathems@mander.xyz 12 points 3 weeks ago

I have absolutely no understanding of whatever is said here

[–] DahGangalang@infosec.pub 6 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

Metric appears to end at 10^30, but even then, I think the better way to phrase that number would be 5,000 quetta-bytes

Tera = 10^12; ~~Septillion~~ Sextillion = 10^21
Source

[–] Redjard@lemmy.dbzer0.com 5 points 3 weeks ago* (last edited 3 weeks ago) (1 children)

*500 000 quettabytes
*Sextillion = 10^21 ( = Zetta)

I'd recommend wikipedia here, your source seems to have taken 3 years to update their table and their image is still outdated.

They likely didn't use quetta because it was only added 3 years ago, and is still not widely known. Or maybe it sounded better.

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