this post was submitted on 07 Dec 2023
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Advent Of Code

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The instructions for part 2 are missing info about how to handle the Four Of A Kind and a joker case. Wasted quite some time because I assumed that the remaining joker would remain unused, but turns out it turns your deck into Five Of A Kind.

Did everybody else just expect this?

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[–] reboot6675@sopuli.xyz 7 points 2 years ago

Why would the joker remain unused? The problem clearly says joker acts as the card that makes the hand strongest, so in this case, 5 of a kind.

[–] Tushta@programming.dev 5 points 2 years ago

There are no suits in this game, so no limit of how many cards of a same kind can be in a hand. Five of a kind is explicitly mentioned in the rules of the game.

[–] TostiHawaii@feddit.nl 2 points 2 years ago

For part 2, the only thing that I missed at first was the JJJJJ edge case. My approach was:

  • count the amount of jokers
  • remove them from the hand
  • count the rest
  • add the amount of jokers to the biggest set in the hand

Last step fails if there are no other cards left after you remove the jokers...