Usually artists go on tour after releasing a new album, to promote said album. So of course they're going to play new stuff.
The ideal for me is a good balance. Some new songs mixed with the classics.
Usually artists go on tour after releasing a new album, to promote said album. So of course they're going to play new stuff.
The ideal for me is a good balance. Some new songs mixed with the classics.
Using a map to store u|v relations. Part 2 sorting with a custom compare function worked very nicely
spoiler
func main() {
file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)
mapPages := make(map[string][]string)
rulesSection := true
middleSumOk := 0
middleSumNotOk := 0
for scanner.Scan() {
line := scanner.Text()
if line == "" {
rulesSection = false
continue
}
if rulesSection {
parts := strings.Split(line, "|")
u, v := parts[0], parts[1]
mapPages[u] = append(mapPages[u], v)
} else {
update := strings.Split(line, ",")
isOk := true
for i := 1; i < len(update); i++ {
u, v := update[i-1], update[i]
if !slices.Contains(mapPages[u], v) {
isOk = false
break
}
}
middlePos := len(update) / 2
if isOk {
middlePage, _ := strconv.Atoi(update[middlePos])
middleSumOk += middlePage
} else {
slices.SortFunc(update, func(u, v string) int {
if slices.Contains(mapPages[u], v) {
return -1
} else if slices.Contains(mapPages[v], u) {
return 1
}
return 0
})
middlePage, _ := strconv.Atoi(update[middlePos])
middleSumNotOk += middlePage
}
}
}
fmt.Println("Part 1:", middleSumOk)
fmt.Println("Part 2:", middleSumNotOk)
}
Same, I initially also thought a|b and a|c implies a|c. However when I drew the graph of the example on paper, I suspected that all relations will be given, and coded it with that assumption, that turned out to be correct
I thought of Ernest & Celestine
Agree, I filled like half notebook with this game
Just a bunch of ifs and bounds checking. Part 2 was actually simpler.
Code
func part1(W [][]rune) {
m := len(W)
n := len(W[0])
xmasCount := 0
for i := 0; i < m; i++ {
for j := 0; j < n; j++ {
if W[i][j] != 'X' {
continue
}
if j < n-3 && W[i][j+1] == 'M' && W[i][j+2] == 'A' && W[i][j+3] == 'S' {
// Horizontal left to right
xmasCount++
}
if j >= 3 && W[i][j-1] == 'M' && W[i][j-2] == 'A' && W[i][j-3] == 'S' {
// Horizontal right to left
xmasCount++
}
if i < m-3 && W[i+1][j] == 'M' && W[i+2][j] == 'A' && W[i+3][j] == 'S' {
// Vertical up to down
xmasCount++
}
if i >= 3 && W[i-1][j] == 'M' && W[i-2][j] == 'A' && W[i-3][j] == 'S' {
// Vertical down to up
xmasCount++
}
if j < n-3 && i < m-3 && W[i+1][j+1] == 'M' && W[i+2][j+2] == 'A' && W[i+3][j+3] == 'S' {
// Diagonal left to right and up to down
xmasCount++
}
if j >= 3 && i < m-3 && W[i+1][j-1] == 'M' && W[i+2][j-2] == 'A' && W[i+3][j-3] == 'S' {
// Diagonal right to left and up to down
xmasCount++
}
if j < n-3 && i >= 3 && W[i-1][j+1] == 'M' && W[i-2][j+2] == 'A' && W[i-3][j+3] == 'S' {
// Diagonal left to right and down to up
xmasCount++
}
if j >= 3 && i >= 3 && W[i-1][j-1] == 'M' && W[i-2][j-2] == 'A' && W[i-3][j-3] == 'S' {
// Diagonal right to left and down to up
xmasCount++
}
}
}
fmt.Println(xmasCount)
}
func part2(W [][]rune) {
m := len(W)
n := len(W[0])
xmasCount := 0
for i := 0; i <= m-3; i++ {
for j := 0; j <= n-3; j++ {
if W[i+1][j+1] != 'A' {
continue
}
if W[i][j] == 'M' && W[i][j+2] == 'M' && W[i+2][j] == 'S' && W[i+2][j+2] == 'S' {
xmasCount++
} else if W[i][j] == 'M' && W[i][j+2] == 'S' && W[i+2][j] == 'M' && W[i+2][j+2] == 'S' {
xmasCount++
} else if W[i][j] == 'S' && W[i][j+2] == 'S' && W[i+2][j] == 'M' && W[i+2][j+2] == 'M' {
xmasCount++
} else if W[i][j] == 'S' && W[i][j+2] == 'M' && W[i+2][j] == 'S' && W[i+2][j+2] == 'M' {
xmasCount++
}
}
}
fmt.Println(xmasCount)
}
func main() {
file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)
var W [][]rune
for scanner.Scan() {
line := scanner.Text()
W = append(W, []rune(line))
}
part1(W)
part2(W)
}
Honestly this is soo much better, I'm not proud of my code at all haha. Thanks for sharing, definitely adding that | to my bag of tricks
Part 1, just find the regex groups, parse to int, and done.
Part 1
func part1() {
file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)
re := regexp.MustCompile(`mul\(([0-9]{1,3}),([0-9]{1,3})\)`)
product := 0
for scanner.Scan() {
line := scanner.Text()
submatches := re.FindAllStringSubmatch(line, -1)
for _, s := range submatches {
a, _ := strconv.Atoi(s[1])
b, _ := strconv.Atoi(s[2])
product += (a * b)
}
}
fmt.Println(product)
}
Part 2, not so simple. Ended up doing some weird hack with a map to check if the multiplication was enabled or not. Also instead of finding regex groups I had to find the indices, and then interpret what those mean... Not very readable code I'm afraid
Part2
func part2() {
file, _ := os.Open("input.txt")
defer file.Close()
scanner := bufio.NewScanner(file)
mulRE := regexp.MustCompile(`mul\(([0-9]{1,3}),([0-9]{1,3})\)`)
doRE := regexp.MustCompile(`do\(\)`)
dontRE := regexp.MustCompile(`don't\(\)`)
product := 0
enabled := true
for scanner.Scan() {
line := scanner.Text()
doIndices := doRE.FindAllStringIndex(line, -1)
dontIndices := dontRE.FindAllStringIndex(line, -1)
mulSubIndices := mulRE.FindAllStringSubmatchIndex(line, -1)
mapIndices := make(map[int]string)
for _, do := range doIndices {
mapIndices[do[0]] = "do"
}
for _, dont := range dontIndices {
mapIndices[dont[0]] = "dont"
}
for _, mul := range mulSubIndices {
mapIndices[mul[0]] = "mul"
}
nextMatch := 0
for i := 0; i < len(line); i++ {
val, ok := mapIndices[i]
if ok && val == "do" {
enabled = true
} else if ok && val == "dont" {
enabled = false
} else if ok && val == "mul" {
if enabled {
match := mulSubIndices[nextMatch]
a, _ := strconv.Atoi(string(line[match[2]:match[3]]))
b, _ := strconv.Atoi(string(line[match[4]:match[5]]))
product += (a * b)
}
nextMatch++
}
}
}
fmt.Println(product)
}
Really cool trick. I did a bunch of regex matching that I'm sure I won't remember how it works few weeks from now, this is so much readable
Go. I actually I haven't written a single line of Go since last year's AoC so it's a good excuse to go again (pun intended).
I liked Digital Minimalism by Cal Newport. I found myself reaching for my phone more often than I would few years back, and doomscrolling at nights, and I got some good tips from this book.
I wouldn't say it solved all of my issues and I will be taking a look at the other books recommended here. But it did help me reduce screen time and focus more on tasks without feeling that I have to look at my phone every 5 minutes.
Agree with Zero Mission. Second would be Dread and then Super. Haven't played Fusion tho, long overdue...